Java中json前后端日期传递处理

JAVA学习网 2018-01-27 06:35:02

这里推荐2种方式

依赖包

        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-core</artifactId>
            <version>${jackson.version}</version>
        </dependency>
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-annotations</artifactId>
            <version>${jackson.version}</version>
        </dependency>
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-databind</artifactId>
            <version>${jackson.version}</version>
        </dependency>

 

1、@JsonFormat

用在属性上即可@JsonFormat(pattern = "yyyy-MM-dd") ,pattern 指定前端传递的日期格式(例如:sj:2018-1-26),

import com.fasterxml.jackson.annotation.JsonFormat;

@JsonFormat(pattern = "yyyy-MM-dd") private Date sj;

 

2@JsonSerialize

也可以自定义,写在属性上即可

import com.fasterxml.jackson.databind.annotation.JsonSerialize;

@JsonSerialize(using=JsonDateSerializer.class) private Date sj;

 


import java.io.IOException;
import java.text.SimpleDateFormat;
import java.util.Date;


import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.SerializerProvider;

public class JsonDateSerializer extends JsonSerializer<Date> {

    @Override
    public void serialize(Date value, JsonGenerator jsGener, SerializerProvider arg2) throws IOException,
            JsonProcessingException {
        SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd");
        String strDate = sf.format(value);
        jsGener.writeString(strDate);
    }

}

这样前端不用再把时间  new  date了,  后端返回也是格式后的时间,而不是时间戳了

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