Python中sys模块sys.argv取值并判断

python学习网 2019-04-22 18:54:04
#!usr/bin/env python
# -*- coding: utf-8 -*-
# Author:Sun Xiaolin

import sys
judgement = sys.argv[1] #[]内写的值表示取第几个
# print(judgement)
if judgement == "1":
    print("")
elif judgement == "2":
    print("")
else:print("请正确输入")

 

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